What is the solution to the system of equations: 2x + y = 10 and x - y = 1?

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Multiple Choice

What is the solution to the system of equations: 2x + y = 10 and x - y = 1?

Explanation:
To find the solution to the system of equations given by \(2x + y = 10\) and \(x - y = 1\), we can solve this system using the method of substitution or elimination. First, let's rearrange the second equation, \(x - y = 1\), to express \(y\) in terms of \(x\): \[ y = x - 1 \] Next, we substitute this expression for \(y\) back into the first equation: \[ 2x + (x - 1) = 10 \] Now, simplify the equation: \[ 2x + x - 1 = 10 \] \[ 3x - 1 = 10 \] Adding 1 to both sides gives: \[ 3x = 11 \] Now, dividing both sides by 3 yields: \[ x = \frac{11}{3} \] Next, we substitute \(x\) back into the expression for \(y\): \[ y = \frac{11}{3} - 1 = \frac{11}{3} - \frac{3}{3} = \frac{8}{3}

To find the solution to the system of equations given by (2x + y = 10) and (x - y = 1), we can solve this system using the method of substitution or elimination.

First, let's rearrange the second equation, (x - y = 1), to express (y) in terms of (x):

[

y = x - 1

]

Next, we substitute this expression for (y) back into the first equation:

[

2x + (x - 1) = 10

]

Now, simplify the equation:

[

2x + x - 1 = 10

]

[

3x - 1 = 10

]

Adding 1 to both sides gives:

[

3x = 11

]

Now, dividing both sides by 3 yields:

[

x = \frac{11}{3}

]

Next, we substitute (x) back into the expression for (y):

[

y = \frac{11}{3} - 1 = \frac{11}{3} - \frac{3}{3} = \frac{8}{3}

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