The simple interest on a loan of $6,000 over 3 years is $900. What is the annual interest rate?

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Multiple Choice

The simple interest on a loan of $6,000 over 3 years is $900. What is the annual interest rate?

Explanation:
To determine the annual interest rate for the loan, we can use the formula for simple interest: \[ I = P \times r \times t \] where: - \( I \) is the interest earned or paid, - \( P \) is the principal amount (the initial amount of the loan), - \( r \) is the annual interest rate (as a decimal), and - \( t \) is the time in years. In this problem: - \( I = 900 \) (the interest earned), - \( P = 6000 \) (the principal), - \( t = 3 \) (the duration of the loan in years). By rearranging the formula to solve for \( r \), we get: \[ r = \frac{I}{P \times t} \] Substituting the values into this equation gives: \[ r = \frac{900}{6000 \times 3} \] Calculating the denominator: \[ 6000 \times 3 = 18000 \] So, we have: \[ r = \frac{900}{18000} = 0.05 \] To convert \( r \) from

To determine the annual interest rate for the loan, we can use the formula for simple interest:

[

I = P \times r \times t

]

where:

  • ( I ) is the interest earned or paid,

  • ( P ) is the principal amount (the initial amount of the loan),

  • ( r ) is the annual interest rate (as a decimal), and

  • ( t ) is the time in years.

In this problem:

  • ( I = 900 ) (the interest earned),

  • ( P = 6000 ) (the principal),

  • ( t = 3 ) (the duration of the loan in years).

By rearranging the formula to solve for ( r ), we get:

[

r = \frac{I}{P \times t}

]

Substituting the values into this equation gives:

[

r = \frac{900}{6000 \times 3}

]

Calculating the denominator:

[

6000 \times 3 = 18000

]

So, we have:

[

r = \frac{900}{18000} = 0.05

]

To convert ( r ) from

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